6=-5t^2+10t+1

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Solution for 6=-5t^2+10t+1 equation:



6=-5t^2+10t+1
We move all terms to the left:
6-(-5t^2+10t+1)=0
We get rid of parentheses
5t^2-10t-1+6=0
We add all the numbers together, and all the variables
5t^2-10t+5=0
a = 5; b = -10; c = +5;
Δ = b2-4ac
Δ = -102-4·5·5
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$t=\frac{-b}{2a}=\frac{10}{10}=1$

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